Prove that the function f given by f (x) = x2 – x + 1 is neither strictly increasing nor strictly decreasing on (– 1, 1).
It is given that function f(x) = x2 – x + 1
f’(x) = 2x – 1
If f’(x) = 0, then we get,
⇒ x = ![]()
So, the point x =
divides the interval (-1,1) into two disjoint intervals,
![]()
So, in interval![]()
f’(x) = 2x – 1 < 0
Therefore, the given function (f) is strictly decreasing in interval ![]()
So, in interval![]()
f’(x) = 2x -1 > 0
Therefore, the given function (f) is strictly increasing in interval for
.
Therefore, f is neither strictly increasing and decreasing in interval (-1,1).