Find the slope of the tangent to curve y = x3 – x + 1 at the point whose x-coordinate is 2.
The given curve is y = x3 – x + 1
Then, the slope of the tangent
= 12 -1 = 11
Therefore, the slope of the tangent 11.
3
Find the slope of the tangent to curve y = x3 – x + 1 at the point whose x-coordinate is 2.
The given curve is y = x3 – x + 1
Then, the slope of the tangent
= 12 -1 = 11
Therefore, the slope of the tangent 11.