Find the equations of the tangent and normal to the given curves at the indicated points:
y = x2 at (0, 0)
It is given that equation of curve is y = x2
On differentiating with respect to x, we get
= 2x
Therefore, the slope of the tangent at (0, 0) is 0.
Then, the equation of the tangent is
y – 0 = 0(x – 0)
⇒ y = 0
Then, slope of normal at (0,0)
=
Now, equation of the normal at (0,0)
x = 0