Find the equations of the tangent and normal to the given curves at the indicated points:
x = cos t, y = sin t at t=π/4
It is given that equation of curve is x = cost, y = sint
On differentiating with respect to x, we get
Therefore, the slope of the tangent at ) is -1.
When
Then, the equation of the tangent is is
y – = -1(x – )
⇒ x + y -- = 0
⇒ x + y - = 0
Then, slope of normal at
=
Now, equation of the normal at
y – = 1(x –)
⇒ x = y