Show that the tangents to the curve y = 7x3 + 11 at the points where x = 2 and
x = – 2 are parallel.
The given curve y = 7x3 + 11
Then, the slope of the tangent to the given curve at x = 4 is given by,
It is cleared that the slopes of the tangents at the points where x = 2 and x = -2 are equal.
Therefore, the two tangents are parallel.