Consider y = √x.

Let x = 25 and Δx = 0.3. Then, we get

Δy = √25.3 - √25

Δy = √25.3 – 5

Δy = √25.3 = Δy + 5

Now, dy is approximately equal to Δy and is given by:

= 0.03

Therefore, the approximate value of is 5.03.