Using differentials, find the approximate value of each of the following up to 3 places of decimal.

Consider y = 
Let x = 1 and Δx = -0.001. Then, we get
Δy = (x+∆x)1/10 - (x)1/10
Δy = (0.999)1/10 - 1
(0.999)1/10 = Δy + 1
Now, dy is approximately equal to Δy and is given by:
dy = 

= -0.0001
Therefore, the approximate value of  is 0.9999.
 is 0.9999.