Using differentials, find the approximate value of each of the following up to 3 places of decimal.

Consider y =


Let x = 400 and Δx = 1. Then, we get


Δy =


=



= Δy + 20


Now, dy is approximately equal to Δy and is given by:


dy =




= 0.025


Therefore, the approximate value of is 20.025.


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