Find the equation of the normal to curve x2 = 4y which passes through the point (1, 2).

Question

Philoid · Accepted Answer

It is given that curve is y² = 4x.

Differentiating with respect to x, we get,

Now, the slope of the normal at point (1,2) is

Therefore, Equation of the normal at (1,2) is y - 2 = - 1(x – 1)

⇒ y - 2 = - x + 1

⇒ x + y - 3 = 0