Find the maximum area of an isosceles triangle inscribed in the ellipse 
 with its vertex at one end of the major axis.
It is given that ellipse ![]()
Let the major axis be along the x – axis.1).
Let ABC be the triangle inscribed in the ellipse where vertex C is at (a,0).
Since, the ellipse is symmetrical w.r.t. x - axis and y - axis, we can assume the coordinates of A to be ( - x1,y1) and the coordinates of B to be ( - x1, - y1).
Now, we have y1 = ± ![]()
Therefore, Coordinates of A 
 and the coordinates of B![]()
As the point(x1,y1) lies on the ellipse, the area of triangle ABC (A) is given by:
A = ![]()
……..(1)



Now, ![]()
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But, x1 cannot be equal to a.
⇒ x1 = ![]()
y1 = ![]()
Now, 


Also, when x1 = 
, then,


 < 0
Then, the area is the maximum when x1 = 
.
Therefore, Maximum area of the triangle is given by:
A = ![]()
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