A point on the hypotenuse of a triangle is at distance a and b from the sides of the triangle.

Show that the maximum length of the hypotenuse is

Let ΔABC be right - angled at B. Let AB = x and BC = y.

Let P be a point on the hypotenuse of the triangle such that P is at a distance of a and b from the sides AB and Bc respectively.


Let <C = θ .


Now, we have,


Ac =


Now, PC = b cosecθ


And AP = a secθ


AC = AP + PC


AC = a secθ + b cosecθ



Now, if


asecθ tanθ = bcosecθ cotθ



asin3θ =bcos3θ




………..(1)


So, it is clear that < 0 when


Therefore, by second derivative test, the length of the hypotenuse is the maximum when


Now, when , we get,


Ac =




Therefore, the maximum length of the hypotenuses is .


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