The normal at the point (1,1) on the curve 2y + x2 = 3 is
It is given that the equation of curve is 2y + x2 = 3
Differentiating w.r.t. x, we get,
The slope of the normal to the given curve at point (1,1) is
Then, the equation of the normal to the curve at (1,1) is
⇒ y – 1 =1(x - 1)
⇒ y - 1 = x – 1
⇒ x – y = 0
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