If x, y, z are nonzero real numbers, then the inverse of matrix is

A =

|A| = x × (y × z) = xyz


Since, |A| ≠ 0


A-1 exists


To find the inverse of a matrix we need to find the Adjoint of that matrix


For finding the adjoint of the matrix we need to find its cofactors


Let Aij denote the cofactors of Matrix A


Minor of an element aij = Mij �


a11 = x, Minor of element a11 = M11 = = (y × z) – (0 × 0) = yz


a12 = 0, Minor of element a12 = M12 = = (0 × z) – (0 × 0) = 0


a13 = 0, Minor of element a13 = M13 = = (0 × 0) – (0 × y) = 0


a21 = 0, Minor of element a21 = M21 = = (0 × z) – (0 × 0) = 0


a22 = y, Minor of element a22 = M22 = = (x × z) – (0 × 0) = xz


a23 = 0, Minor of element a23 = M23 = = (x × 0) – (0 × 0) = 0


a31 = 0, Minor of element a31 = M31 = = (z × 0) – (0 × 0) = 0


a32 = 0, Minor of element a32 = M32 = = (x × 0) – (0 × 0) = 0


a33 = z, Minor of element a33 = M33 = = (x × y) – (0 × 0) = xy


Cofactor of an element aij, Aij = (-1)i+j × Mij


A11 = (-1)1+1× M11 = 1 × yz = yz


A12 = (-1)1+2× M12 = (-1) × 0 = 0


A13 = (-1)1+3× M13 = 1 × 0 = 0


A21 = (-1)2+1× M21 = (-1) × 0 = 0


A22 = (-1)2+2 × M22 = 1 × xz = xz


A23 = (-1)2+3 × M23 = (-1) × 0 = 0


A31 = (-1)3+1 × M31 = 1 × 0 = 0


A32 = (-1)3+2 × M32 = (-1) × 0 = 0


A33 = (-1)3+3 × M33 = 1 × xy = xy


Adj A = =


A-1 = adj A / |A|


A-1 = /xyz


A-1 =


A-1 = =


The correct answer is A

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