If A is square matrix such that A2 = A, then (I + A) � – 7 A is equal to

Given that A2 = A

Calculating value of (I + A) � – 7 A:


I3 + A3 + 3I2A + 3IA2 – 7A


I + A2.A + 3A + 3A2 – 7A (In = I and I.A = A)


I + A.A + 3A + 3A – 7A (A2 = A)


I + A2 + 3A + 3A – 7A


I + A - A


I


Hence (I + A) � – 7 A = I.

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