Henry’s law constant for CO 2 in water is 1.67x10 8 Pa at 298 K. Calculate the quantity of CO 2 in 500 mL of soda water when packed under 2.5 atmCO 2 pressure at 298 K.

Question

Philoid · Accepted Answer

According to Henry's law,

'At a constant temperature, the amount of a given gas that dissolves in a given type and volume of liquid is directly proportional to the partial pressure of that gas in equilibrium with that liquid.'

Stated as,

p = K_Hx

Where,

P = partial pressure of the solute above the solution

K_H = Henry's constant

x = concentration of the solute in the solution

Given,

KH = 1.67x10⁸ Pa

P_CO2 2.5 atm = 2.5 × 1.01325 × 10⁵Pa

According to Henry's law,

p = K_Hx

x = 0.00152

In 500 ml of soda water there is 500 ml of water (neglecting soda)

Mole of water =

= 27.78 mol

Now,

x =

n_CO2 = x n_H2O

= 0.00152 × 27.78

= 0.042 mol

Hence, quantity of CO₂ in 500mL of soda water 0.042 × 44 = 1.848 g

Henry’s law constant for CO2 in water is 1.67x108 Pa at 298 K. Calculate the quantity of CO2 in 500 mL of soda water when packed under 2.5 atmCO2 pressure at 298 K.

Henry’s law constant for CO₂ in water is 1.67x10⁸ Pa at 298 K. Calculate the quantity of CO₂ in 500 mL of soda water when packed under 2.5 atmCO₂ pressure at 298 K.