If the density of some lake water is 1.25g/ml and contains 92 g of Na+ ions per kg of water, calculate the molality of Na+ ions in the lake.
Mass of ions = 92g
Molar mass of ions = Na+ = 23g(neglect the mass lost due to absence of a electron)
Moles of ions = mass of ions/molar mass
⇒ n = 92/23 moles
⇒ n = 4moles
Molality of solution = moles of solute/mass of solvent(in kg)
Molality = 4/1 = 4M