Henry’s law constant for the molality of methane in benzene at 298 K is 4.27 × 10 5 mm Hg. Calculate the solubility of methane in benzene at 298 K under 760 mm Hg.

Question

Philoid · Accepted Answer

Given-

Henry’s law constant K_H = 4.27X 10⁵ mm Hg,

p = 760mm Hg,

Using Henry’s law,

→

∴

Using the formula of lowering vapour pressure,

→ Equation 1

Since, <<<, the Equation 1 is rewritten as,

→

where and = molarity of benzene

∴

Thus, the solubility of methane in benzene is 0.023 moles

Henry’s law constant for the molality of methane in benzene at 298 K is 4.27 × 105 mm Hg. Calculate the solubility of methane in benzene at 298 K under 760 mm Hg.

Henry’s law constant for the molality of methane in benzene at 298 K is 4.27 × 10⁵ mm Hg. Calculate the solubility of methane in benzene at 298 K under 760 mm Hg.