Determine the osmotic pressure of a solution prepared by dissolving 25 mg of K2SO4 in 2 litre of water at 25° C, assuming that it is completely dissociated.

Given-


Mass of K2SO4, w = 25 mg = g,


Molar mass of K2SO4 = (39×2) + (32×1) + (16×4) = 174 g mol-1


Volume V = 2 liter


T = 250C + 273 = 298 K (add 273 to convert in Kelvin)


The reaction of dissociation of K2SO4 is written as,


K2SO4 2K + + SO42-


Number if ions produced = 2 + 1 = 3, hence vant Hoff’s factor, i = 3


Here, we use vant Hoff’s equation for dilute solutions, given as,



where, n is the number of moles of solute, R is solution constant which is equal to the gas constant(0.082) and T is the absolute temperature (298 K).






Hence, the osmotic pressure of a solution is 5.27x10-3atm


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