Determine the osmotic pressure of a solution prepared by dissolving 25 mg of K2SO4 in 2 litre of water at 25° C, assuming that it is completely dissociated.
Given-
Mass of K2SO4, w = 25 mg = g,
Molar mass of K2SO4 = (39×2) + (32×1) + (16×4) = 174 g mol-1
Volume V = 2 liter
T = 250C + 273 = 298 K (add 273 to convert in Kelvin)
The reaction of dissociation of K2SO4 is written as,
K2SO4 → 2K + + SO42-
Number if ions produced = 2 + 1 = 3, hence vant Hoff’s factor, i = 3
Here, we use vant Hoff’s equation for dilute solutions, given as,
→
where, n is the number of moles of solute, R is solution constant which is equal to the gas constant(0.082) and T is the absolute temperature (298 K).
Hence, the osmotic pressure of a solution is 5.27x10-3atm