Calculate the emf of the cell in which the following reaction takes place:
Ni(S) + 2Ag+ (0.002M) → Ni2+ (0.160 M) + 2Ag(s)
Given that
Given:
[Ag+] = 0.002 M
[Ni2+] = 0.160 M
n = 2
(n = moles of e- from balanced redox reaction)
E0cell= 1.05 V
Now, using the Nernst equation we get,
⇒