The conductivity of 0.20 M solution of KCl at 298 K is 0.0248 S cm–1. Calculate its molar conductivity.
Given -
Molarity, C = 0.20 M
Electrolytic conductivity of a solution, κ = 0.0248 S cm–1
Molar conductivity = ?
Molar conductivity, ∧m = S cm2 mol-1
∴ ∧m = 124 S cm2 mol-1
Molar conductivity(∧m) of 0.20 M solution of KCl at 298 K is 124 S cm2 mol-1