(i)The electrode reaction for 1 mole of H₂O is given as,

H₂O → H₂ + O₂

i.e., O^{2 -} →O₂ + 2e ^-

∴ The quantity of electricity required = 2F

= 2×96487 C

= 192974 C

The quantity of electricity required in coulomb for the oxidation of 1 mol of H₂O to O₂ is 192974 C

(ii) The electrode reaction for 1 mole of FeO is

FeO + O₂ → Fe₂O₃

i.e., Fe^{2 +} → Fe^{3 +} + e ^-

∴ The quantity of electricity required = 1F

= 1×96487 C

= 96487 C

The quantity of electricity required in coulomb for the oxidation of 1 mol of FeO to Fe₂O₃ is 96487 C