In a reaction, 2A → Products, the concentration of A decreases from 0.5 mol L^{–}^{1} to 0.4 mol L^{–}^{1} in 10 minutes. Calculate the rate during this interval?

Given-

Initial concentration(A_{1}) = 0.5M

Final concentration(A_{2}) = 0.4M

Time = 10 mins.

The formula for average rate of the reaction is,

→ Equation 1

∵ {A} = (A_{2})-( A_{1}), the equation 1 is written as,

=

= 0.005 mol L^{-1} min^{-1}

= 5 × 10^{-3} mol L^{-1} min^{-1}

__The average rate of the reaction is__ __5 × 10 ^{-3} mol L^{-1} min^{-1}__

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