The conversion of molecules X to Y follows second order kinetics. If concentration of X is increased to three times how will it affect the rate of formation of Y ?
Let the reaction be X→Y
As, this reaction follows second order kinetics, the rate of the reaction will be,
Rate = k(X)2 → Equation 1
Since the concentration of X is increased three times, Equation 1
will become,
Rate = k(3X)2
= k × 9(X)2
∴ The rate of formation of Y will become 9 times.
Thus, the rate of formation of Y will become 9 times