The decomposition of dimethyl ether leads to formation of CH_{4}, H_{2} and CO and the reaction rate is given by,

Rate = k[CH_{3}OCH_{3}]^{3/2}. The rate of reaction is followed by an increase in pressure in a closed vessel, so the rate can also be expressed in terms of the partial pressure of dimethyl ether i.e. Rate = k[pCH_{3}OCH_{3}]^{3/2}. If the pressure is measured in bar and time in minutes, then what are the units of rate and rate constants?

Rate of given chemical reaction will be represented as

.

Hence units of rate is bar min^{-1}

To find units of K, K = rate/[pCH_{3}OCH_{3}]^{3/2}

The unit of k = bar ^{-1/2}min^{-1}.

__Units of Rate- bar min ^{-1}. and Units of Rate constant K : bar ^{-1/2}min ^{-1}__

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