Sucrose decomposes in acid solution into glucose and fructose according to the first order rate law, with t 1/2 = 3.00 hours. What fraction of sample of sucrose remains after 8 hours?

Question

Philoid · Accepted Answer

t_1/2 = 3.00 hours

We know, t_1/2 = 0.693/k

∴ k = 0.693/3

k = 0.231hrs^-1

We know, time

Where, k- rate constant

[R]_° -Initial concentration

[R]-Concentration at time ‘t’

Thus, substituting the values,

log([R]₀/[R]) = 0.8

log([R]/[R]₀) = -0.8

[R]/[R]₀ = 0.158

Hence, 0.158 fraction of sucrose remains.

Sucrose decomposes in acid solution into glucose and fructose according to the first order rate law, with t1/2 = 3.00 hours. What fraction of sample of sucrose remains after 8 hours?

Sucrose decomposes in acid solution into glucose and fructose according to the first order rate law, with t_1/2 = 3.00 hours. What fraction of sample of sucrose remains after 8 hours?