It is given that at x = 1, the function x4 – 62x2 + ax + 9 attains its maximum value, on the interval [0, 2]. Find the value of a.
It is given that f(x) = x4 – 62x2 + ax + 9
Then, f’(x) = 4x3 – 124x+ a
It is given that function f attains its maximum value on the interval [0, 2] at x = 1.
⇒ f’(1) = 0
⇒ 4 – 124 + a = 0
⇒ a = 120
Therefore, the value of a is 120.