Calculate the number of unpaired electrons in the following gaseous ions: Mn3+, Cr3+, V3+, and Ti3+. Which one of these is the most stable in aqueous solution?
From the table given below:
Mn3+ : 3d4 | unpaired electrons = 4 |
V3+ : 3d2 | unpaired electrons =2 |
Cr3+ : 3d3 | unpaired electrons= 3 |
Ti3+ : 3d1 | unpaired electrons =1 |
Cr3+ is most stable in aqueous solution because of half filled d-orbital.