Let us assume the ones digit be x and the tens digit be y

According to the question, we have

x + y = 10 …(i)

(10y + x) – 18 = 10x + y

x – y = – 2 …(ii)

Now, adding (i) and (ii) we get:

2x = 8

Now by putting the value of x in (i), we get

4 + y = 10

y = 10 – 4

y = 6

Hence the required number is 64