The given two equations are:

kx – y – 2 = 0 …(i)

6x – 2y – 3 = 0 …(ii)

Here, we have:

a₁ = k, b₁ = – 1 and c₁ = – 2

a₂ = 6, b₂ = – 2 and c₂ = – 3

We know that, for the system having a unique solution we must have

∴