Find k for which the system 2x + 3y – 5 = 0, 4x + ky – 10 = 0 has a infinite number of solution.
The given two equations are:
2x + 3y – 5 = 0 …(i)
4x + ky – 10 = 0 …(ii)
Here, we have:
a1 = 2, b1 = 3 and c1 = – 5
a2 = 4, b2 = k and c2 = – 10
We know that, for the system having a infinite number of solutions we must have
∴ k = 6
Hence, the value of k is 6