The given two equations are:

…(i)

…(ii)

Now, substituting and in (i) and (ii) the given equation will changed to:

3u + 2v = 2 …(iii)

9u – 4v = 1 …(iv)

Now, by multiplying (i) by 2 and adding it with (ii) we get:

15u = 4 + 1

Also, by multiplying (i) by 3 and subtracting it from (ii) we get:

6u + 4v = 6 – 1

∴ x + y = 3 …(v)

And, x – y = 2 …(vi)

Now, adding (v) and (vi) we get:

2x = 5

Now substituting the value of x in (v), we get: