Solve: and

The given two equations are:

…(i)


…(ii)


Now, substituting and in (i) and (ii) the given equation will changed to:


3u + 2v = 2 …(iii)


9u – 4v = 1 …(iv)


Now, by multiplying (i) by 2 and adding it with (ii) we get:


15u = 4 + 1



Also, by multiplying (i) by 3 and subtracting it from (ii) we get:


6u + 4v = 6 – 1



x + y = 3 …(v)


And, x – y = 2 …(vi)


Now, adding (v) and (vi) we get:


2x = 5



Now substituting the value of x in (v), we get:






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