If 2x + 3y = 12 and 3x – 2y = 5 then
We have:
2x + 3y = 12 …(i)
3x – 2y = 5 …(ii)
Now, by multiplying (i) by 2 and (ii) by 3 and then adding them we get:
4x + 9x = 24 + 15
13x = 39
Now putting the value of x in (i), we get
2 × 3 + 3y = 12
∴
Hence, option C is correct