First of all we have to consider,

and

By simplifying above equations, we get:

3 (2x + y + 2) = 5 (3x – y + 1)

6x + 3y + 6 = 15x – 5y + 5

9x – 8y = 1 …(i)

And, 6 (3x – y + 1) = 3 (3x + 2y + 1)

18x – 6y + 6 = 9x + 6y + 3

3x – 4y = – 1 …(ii)

Now, multiplying (ii) by 2 and then subtracting it from (i) we get:

9x – 6x = 1 + 2

∴ x = 1

Putting the value of x in (ii), we get

3 × 1 – 4y = – 1

∴

Hence, option A is correct