If the lines given by 3x + 2ky = 2 and 2x + 5y + 1 = 0 are parallel then the value of k is

We have,

3x + 2ky – 2 = 0


And, 2x + 5y + 1 = 0


Here, a1 = 3, b1 = 2k and c1 = – 2


a2 = 2, b2 = 5 and c2 = 1




And,


We know that, for the system having parallel lines we must have:





Hence, option D is correct

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