For what value of k do the equations kx – 2y = 3 and 3x + y = 5 represent two lines intersecting at a unique point?
We have,
kx – 2y – 3 = 0
And, 3x + y – 5 = 0
Here, a1 = k, b1 = – 2 and c1 = – 3
a2 = 3, b2 = 1 and c2 = – 5
∴
And,
We know that, for these graphs intersect at a unique point we must have:
Hence, the lines of the graph will intersect at all real values of k except – 6
Thus, option D is correct