We have,

x + 2y + 5 = 0

And, – 3x – 6y + 1 = 0

Here, a₁ = 1, b₁ = 2 and c₁ = 5

a₂ = – 3, b₂ = – 6 and c₂ = 1

∴

And,

∴

Hence, the given system has no solution

Thus, option D is correct