5 years hence, the age of a man shall be 3 times the age of his son while 5 years earlier the age of the man was 7 times the age of his son. The present age of the man is

Let us assume the present age of men be x years

Also, the present age of his son be y years


According to question, after 5 years:


(x + 5) = 3 (y + 5)


x + 5 = 3y + 15


x – 3y = 10 …(i)


Also, five years ago:


(x – 5) = 7 (y – 5)


x – 5 = 7y – 35


x – 7y = – 30 …(ii)


Now, on subtracting (i) from (ii) we get:


– 4y = – 40


y = 10


Putting the value of y in (i), we get


x – 3 × 10 = 10


x – 30 = 10


x = 10 + 30


x = 40


The present age of men is 40 years


Hence, option D is correct

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