5 years hence, the age of a man shall be 3 times the age of his son while 5 years earlier the age of the man was 7 times the age of his son. The present age of the man is
Let us assume the present age of men be x years
Also, the present age of his son be y years
According to question, after 5 years:
(x + 5) = 3 (y + 5)
x + 5 = 3y + 15
x – 3y = 10 …(i)
Also, five years ago:
(x – 5) = 7 (y – 5)
x – 5 = 7y – 35
x – 7y = – 30 …(ii)
Now, on subtracting (i) from (ii) we get:
– 4y = – 40
y = 10
Putting the value of y in (i), we get
x – 3 × 10 = 10
x – 30 = 10
x = 10 + 30
x = 40
∴ The present age of men is 40 years
Hence, option D is correct