The graphs of the equations 2x + 3y – 2 = 0 and x – 2y – 8 = 0 are two lines which are

We have,

2x + 3y – 2 = 0


And, x – 2y – 8 = 0


Here, a1 = 2, b1 = 3 and c1 = – 2


And, a2 = 1, b2 = – 2 and c2 = – 8


, and


Clearly,


Hence, the given system has a unique solution and the lines intersect exactly at one point


Option C is correct

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