The graphs of the equations 2x + 3y – 2 = 0 and x – 2y – 8 = 0 are two lines which are
We have,
2x + 3y – 2 = 0
And, x – 2y – 8 = 0
Here, a1 = 2, b1 = 3 and c1 = – 2
And, a2 = 1, b2 = – 2 and c2 = – 8
∴ ,
and
Clearly,
Hence, the given system has a unique solution and the lines intersect exactly at one point
∴ Option C is correct