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Which of the following are quadratic equations in x?
The given equation is a quadratic equation.
Explanation - It is of degree 2, it is in the form (a ≠ 0, a, b, c are real numbers)
where a = √2, b = 7, c = 5√2.
x2 - x + 3 = 0
(x + 2)3 = x3 – 8
2x + 3)(3x + 2) = 6(x - 1)(x - 2)
Which of the following are the roots of 3x2 + 2x - 1 = 0 ?
(i) - 1 (ii) 1/3 (iii) –1/2
Find the value of k for which x = 1 is a root of the equation x2 + kx + 3 = 0. Also, find the other root.
Find the values of a or b for which x = 3/4 or x = - 2 are the roots of the equation
ax2 + bx – 6 = 0
Solve each of the following quadratic equations:
(2x-3) (3x + 1) = 0
4x2 + 5x = 0
3x2 – 243 = 0
2x2 + x - 6 = 0
x2 + 6x + 5 = 0
9x2 - 3x - 2 = 0
x2 + 12x + 35 = 0
x2 = 18x – 77
6x2 + 11x + 3 = 0
6x2 + x - 12 = 0
3x2 - 2x - 1 = 0
4x2 - 9x = 100
15x2 - 28 = x
4 - 11x = 3x2
48x2 - 13x - 1 = 0
x2 + 2√2 x – 6 = 0
√3x2 + 10x + 7√3 = 0
√3x2 + 11x + 6√3 = 0
3√7x2 + 4x – √7 = 0
√7x2 – 6x – 13√7 = 0
4√6x2 – 13 x – 2√6 = 0
3x2 – 2√6x + 2 = 0
√3x2 – 2√2x – 2√3 = 0
x2 – 3√5x + 10 = 0
x2 – (√3 + 1) x + √3 = 0
x2 + 3√3x – 30 = 0
√2x2 + 7x + 5√2 = 0
5x2 + 13x + 8 = 0
x2 – (1+ √2)x + √2 = 0
9x2 + 6x + 1 = 0
100x2 - 20x + 1 = 0
2x2 + ax - a2 = 0
4x2 + 4bx - (a2 - b2) = 0
4x2 - 4a2x + (a4 - b4) = 0
x2 + 5x - (a2 + a - 6) = 0
x2 - 2ax - (4b2 - a2) = 0
x2 - (2b - 1)x + (b2 - b - 20) = 0
x2 + 6x - (a2 + 2a - 8) = 0
abx2 + (b2 - ac)x - bc = 0
x2 - 4ax - b2 + 4a2 = 0
4x2 - 2 (a2 + b2) x + a2b2 = 0
12abx2 - (9a2 - 8b2)x - 6ab = 0
a2b2x2 + b2x - a2x - 1 = 0
9x2 - 9 (a + b)x + (2 a2 + 5ab + 2b2) = 0
3(x + 2) + 3 - x = 10
4(x + 1) + 4(1 - x) = 10
22x - 3.2(x + 2) + 32 = 0