 ## Book: RS Aggarwal - Mathematics

#### Subject: Maths - Class 10th

##### Q. No. 13 of Exercise 10A

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13
##### Solve each of the following quadratic equations:6x2 + 11x + 3 = 0 Using the splitting middle term - the middle term of the general equation is divided in two such values that:

Product = a.c

For the given equation a = 6; b = 11; c = 3

= 6.3 = 18

And either of their sum or difference = b

= 11

Thus the two terms are 9 and 2

Sum = 9 + 2 = 11

Product = 9.2 = 18  3x(2x + 3) + 1(2x + 3) = 0

(3x + 1)(2x + 3) = 0

(3x + 1) = 0 or (2x + 3) = 0

x = (-1)/3 or x = (-3)/2

Roots of equation are , 1
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