Solve each of the following quadratic equations:
6x2 + 11x + 3 = 0
Using the splitting middle term - the middle term of the general equation is divided in two such values that:
Product = a.c
For the given equation a = 6; b = 11; c = 3
= 6.3 = 18
And either of their sum or difference = b
= 11
Thus the two terms are 9 and 2
Sum = 9 + 2 = 11
Product = 9.2 = 18
3x(2x + 3) + 1(2x + 3) = 0
(3x + 1)(2x + 3) = 0
(3x + 1) = 0 or (2x + 3) = 0
x = (-1)/3 or x = (-3)/2
Roots of equation are ,