Solve each of the following quadratic equations:

6x2 + 11x + 3 = 0


Using the splitting middle term - the middle term of the general equation is divided in two such values that:


Product = a.c


For the given equation a = 6; b = 11; c = 3


= 6.3 = 18


And either of their sum or difference = b


= 11


Thus the two terms are 9 and 2


Sum = 9 + 2 = 11


Product = 9.2 = 18




3x(2x + 3) + 1(2x + 3) = 0


(3x + 1)(2x + 3) = 0


(3x + 1) = 0 or (2x + 3) = 0


x = (-1)/3 or x = (-3)/2


Roots of equation are ,


13