Book: RS Aggarwal - Mathematics
Chapter: 10. Quadratic Equations
Subject: Maths - Class 10th
Q. No. 14 of Exercise 10A
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14
Solve each of the following quadratic equations:
6x2 + x - 12 = 0
Using the splitting middle term - the middle term of the general equation 
is divided in two such values that:
Product = a.c
For the given equation a = 6; b = 1; c = -12
= 6. - 12 = - 72
And either of their sum or difference = b
= 1
Thus the two terms are 9 and - 8
Difference = 9 - 8 = 1
Product = 9. - 8 = - 72
3x(2x + 3)-4(2x + 3) = 0
(2x + 3)(3x-4) = 0
(2x + 3) = 0 or (3x-4) = 0
x = (-3)/2 or x = 4/3
Roots of equation are 
, 
14
