Book: RS Aggarwal - Mathematics
Chapter: 10. Quadratic Equations
Subject: Maths - Class 10th
Q. No. 19 of Exercise 10A
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19
Solve each of the following quadratic equations:
48x2 - 13x - 1 = 0
Using the splitting middle term - the middle term of the general equation 
is divided in two such values that:
Product = a.c
For the given equation a = 48; b = -13 ;c = -1
= 48× - 1 = - 48
And either of their sum or difference = b
= - 13
Thus the two terms are - 16 and 3
Difference = - 16 + 3 = - 13
Product = - 16.3 = - 48
16x(3x-1) + 1(3x-1) = 0
(16x + 1)(3x-1) = 0
(16x + 1) = 0 or (3x-1) = 0
x = (-1)/6 or x = 1/3
Roots of equation are 
