Solve each of the following quadratic equations:

√3x2 + 10x + 7√3 = 0


Using the splitting middle term - the middle term of the general equation is divided in two such values that:


Product = a.c


For the given equation a = √3 ;b = 10; c = 7√3


= √3.7√3 = 21


(using 3 = √3×√3)


And either of their sum or difference = b


= 10


Thus, the two terms are 7 and 3


Sum = 7 + 3 = 10


Product = 7.3 = 21



(using )






Roots of equation are


21