Solve each of the following quadratic equations:

√3x2 + 11x + 6√3 = 0


Using the splitting middle term - the middle term of the general equation is divided in two such values that:


Product = a.c


For the given equation a = √(3;) b = 11; c = 6√3


= √3.6√3 = 3.6 = 18


(using 3 = √3.√3


And either of their sum or difference = b


= 11


Thus the two terms are 9 and 2


Sum = 9 + 2 = 11


Product = 9.2 = 18




√3 x(x + 3√3) + 2(x + 3√3) = 0


(using 9 = 3.3 = 3√3 √3)


(√3 x + 2)(x + 3√3) = 0


(√3 x + 2)(x + 3√3) = 0



Roots of equation are


22