Book: RS Aggarwal - Mathematics
Chapter: 10. Quadratic Equations
Subject: Maths - Class 10th
Q. No. 22 of Exercise 10A
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22
Solve each of the following quadratic equations:
√3x2 + 11x + 6√3 = 0
Using the splitting middle term - the middle term of the general equation 
is divided in two such values that:
Product = a.c
For the given equation a = √(3;) b = 11; c = 6√3
= √3.6√3 = 3.6 = 18
(using 3 = √3.√3
And either of their sum or difference = b
= 11
Thus the two terms are 9 and 2
Sum = 9 + 2 = 11
Product = 9.2 = 18
√3 x(x + 3√3) + 2(x + 3√3) = 0
(using 9 = 3.3 = 3√3 √3)
(√3 x + 2)(x + 3√3) = 0
(√3 x + 2)(x + 3√3) = 0
Roots of equation are
