 ## Book: RS Aggarwal - Mathematics

#### Subject: Maths - Class 10th

##### Q. No. 23 of Exercise 10A

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23
##### Solve each of the following quadratic equations:3√7x2 + 4x – √7 = 0 Using the splitting middle term - the middle term of the general equation is divided in two such values that:

Product = a.c

For the given equation a = 3√7 ;b = 4 ;c = -√7

= 3√7.-√7 = 3.-7 = -21

(using 7 = √7.√7)

And either of their sum or difference = b

= 4

Thus the two terms are 7 and - 3

Difference = 7 - 3 = 4

Product = 7× - 3 = - 21  ( using 7 = √7.√7) (√7 x-1)(3x + √7) = 0

(√7 x-1) = 0 or (3x + √7) = 0

x = 1/√7 or x = (-7)/√3

Roots of equation are 1
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