Book: RS Aggarwal - Mathematics
Chapter: 10. Quadratic Equations
Subject: Maths - Class 10th
Q. No. 24 of Exercise 10A
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24
Solve each of the following quadratic equations:
√7x2 – 6x – 13√7 = 0
Using the splitting middle term - the middle term of the general equation 
is divided in two such values that:
Product = a.c
For the given equation 
= √7.-13√7 = -13.7 = -91
And either of their sum or difference = b
= - 6
Thus the two terms are 7 and - 13
Difference = - 13 + 7 = - 6
Product = 7. - 13 = - 91
x(√7 x-13) + √7 (√7 x-13) = 0
(x + √7)(√7 x-13) = 0
(x + √7) = 0 or (√7 x-13) = 0
x = -√7 or x = 13/√7
Roots of equation are 
