Book: RS Aggarwal - Mathematics
Chapter: 10. Quadratic Equations
Subject: Maths - Class 10th
Q. No. 25 of Exercise 10A
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25
Solve each of the following quadratic equations:
4√6x2 – 13 x – 2√6 = 0
Using the splitting middle term - the middle term of the general equation 
is divided in two such values that:
Product = a.c
For the given equation a = 4√6 ;b = -13 ;c = -2√6
= 4√6.-2√6 = -48
And either of their sum or difference = b
= - 13
Thus the two terms are - 16 and 3
Difference = - 16 + 3 = - 13
Product = - 16.3 = - 48
(On using √6 = √3 √2 and 16 = 4.2.√2 √2 )
⇒ (4√2 x + √3)(√3 x-2√2) = 0
⇒ (4√2 x + √3) = 0 or (√3 x-2√2) = 0
x = (-√3)/(4√2 ) or x = (2√2)/√3
Roots of equation are 
