 ## Book: RS Aggarwal - Mathematics

#### Subject: Maths - Class 10th

##### Q. No. 25 of Exercise 10A

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25
##### Solve each of the following quadratic equations:4√6x2 – 13 x – 2√6 = 0 Using the splitting middle term - the middle term of the general equation is divided in two such values that:

Product = a.c

For the given equation a = 4√6 ;b = -13 ;c = -2√6

= 4√6.-2√6 = -48

And either of their sum or difference = b

= - 13

Thus the two terms are - 16 and 3

Difference = - 16 + 3 = - 13

Product = - 16.3 = - 48   (On using √6 = √3 √2 and 16 = 4.2.√2 √2 )

(4√2 x + √3)(√3 x-2√2) = 0

(4√2 x + √3) = 0 or (√3 x-2√2) = 0

x = (-√3)/(4√2 ) or x = (2√2)/√3

Roots of equation are 1
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