Book: RS Aggarwal - Mathematics
Chapter: 10. Quadratic Equations
Subject: Maths - Class 10th
Q. No. 27 of Exercise 10A
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27
Solve each of the following quadratic equations:
√3x2 – 2√2x – 2√3 = 0
Using the splitting middle term - the middle term of the general equation 
is divided in two such values that:
Product = a.c
For the given equation a = √3 b = -2√2 c = -2√3
= √3.-2√3 = -2.3 = -6
And either of their sum or difference = b
= -2√2
Thus the two terms are -3√2 and √2
Difference = -3√2 + √2 = -2√2
Product = -3√2 × √2 = -3.2 = -6
(On using3√2 = √3 √3 √2 = √3.√6)
(∵2√3 = √2 √2 √3 = √2.√6)
Roots of equation are 
