Solve each of the following quadratic equations:
taking LCM
3x2 + 2x - 1 = 14x - 10 cross multiplying
3x2 - 12x + 9 = 0 taking 3 common
x2 - 4x + 3 = 0
Using the splitting middle term - the middle term of the general equation is divided in two such values that:
Product = a.c
For the given equation a = 1 b = - 4 c = 3
= 1.3 = 3
And either of their sum or difference = b
= - 4
Thus the two terms are - 3 and - 1
Sum = - 3 - 1 = - 4
Product = - 3. - 1 = 3
x2 - 4x + 3 = 0
x2 - 3x - x + 3 = 0
x(x - 3) - 1(x - 3) = 0
(x - 3) (x - 1) = 0
(x - 3) = 0 or (x - 1) = 0
x = 3 or x = 1
Hence the roots of equation are 3 or1.