Solve each of the following quadratic equations:



taking LCM



4x2 + 4ax + 2bx = - 2ab cross multiplying


4x2 + 4ax + 2bx + 2ab = 0


4x(x + a) + 2b(x + a) = 0 taking 4x common from first two terms and 2b from last two


(x + a) (4x + 2b) = 0


(x + a) = 0 or (4x + 2b) = 0



Hence the roots of equation are


56